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Pexpect help needed - Printable Version

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Pexpect help needed - jash - Jan-30-2018

I'm new to Python programming and I'm trying to ssh using the pexpect code but it fails when I enter the password. Can someone please look into it. Also, Is there a tutorial for pexpect for automating the networking. Please suggest!
Thanks!

#!/usr/bin/env python
import pexpect

ssh_newkey = 'Are you sure you want to continue connecting'
# my ssh command line
p=pexpect.spawn('ssh [email protected] uname -a')

i=p.expect([ssh_newkey,'Password:',pexpect.EOF])
if i==0:
    print "I say yes"
    p.sendline('yes')
    i=p.expect([ssh_newkey,'password:',pexpect.EOF])
if i==1:
    print "I give password",
    p.sendline(password)     //// fails here
    p.expect(pexpect.EOF)    
elif i==2:
    print "I either got key or connection timeout"
    pass
print p.before # print out the result
Error:
Error:
File "test/ssh3.py", line 15
    p.sendline(pasword)
                    ^
SyntaxError: invalid syntax
This is the entire program. I'm trying to check if I can ssh into the device successfully or not. Thanks!

RE: Pexpect help needed - micseydel - Jan-30-2018

Doing all the sane things I can think of, I can't figure out why you're getting a syntax error with this code. Please copy-paste your own code, remove the /// thing, and verify that you're really getting this issue with the code you've posted (rather than some other code).

RE: Pexpect help needed - jash - Jan-30-2018 

#!/usr/bin/env python
import pexpect

ssh_newkey = 'Are you sure you want to continue connecting'
# my ssh command line
p=pexpect.spawn('ssh [email protected] uname -a')

i=p.expect([ssh_newkey,'Password:',pexpect.EOF])
if i==0:
    print "I say yes"
    p.sendline('yes')
    i=p.expect([ssh_newkey,'password:',pexpect.EOF])
if i==1:
    print "I give password",
    p.sendline(admin123)     
    p.expect(pexpect.EOF)    
elif i==2:
    print "I either got key or connection timeout"
    pass
print p.before # print out the result
Error:
python test/ssh3.py
  File "test/ssh3.py", line 15
    p.sendline(admin123)
                    ^
SyntaxError: invalid syntax
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