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+--- Thread: pyython code copied 1to1 from book not working. (/thread-8449.html)
pyython code copied 1to1 from book not working. - BlackReptile - Feb-21-2018
Hello im a Programming Beginner and learning form a book. Everything worked so far extemley well and im making Progress but this Python Script doesnt seem to work. I get syntax error on ELIF and i dont know why.
#initzialize random number generator
import random
random.seed()
#init variables
a = random.randint(1,100)
b = random.randint(1,100)
c = a + b
#Question
print ("Die Aufgabe lautet:", a, b)
#userinput
print ("Bitte Zahl eingeben:")
zahl = input()
zahl = float(zahl)
#results
if zahl == c:
print("Super Das Ergebnis ist richtig")
elif zahl < 0 or zahl > 100:
print("Ganz Falsch")
elif zahl c-1 <= zahl <= c+1: #in this line im getting syntax error. ELIF is red underlined. and i dont know why
print("Du bist ganz nahe dran")
else:
print("Falsch")Thank You For your Help :)
RE: pyython code copied 1to1 from book not working. - Windspar - Feb-21-2018
line 25
elif zahl(EXTRA zahl or SOMETHING_MISSING_HERE) c-1 <= zahl <= c+1:
RE: pyython code copied 1to1 from book not working. - abhin - Feb-21-2018
You probably wanted line 25-26 to be
elif c-1 <= zahl <= c+1:
print("Du bist ganz nahe dran")