Accessing data in zip - Index out of range

Accessing data in zip - Index out of range - Printable Version

+- Python Forum (https://python-forum.io)
+-- Forum: Python Coding (https://python-forum.io/forum-7.html)
+--- Forum: Homework (https://python-forum.io/forum-9.html)
+--- Thread: Accessing data in zip - Index out of range (/thread-8683.html)

Pages: 1 2 3

Accessing data in zip - Index out of range - pythoneer - Mar-03-2018

i have 3 lists

Quote:Names=["Jack","Jeni","Monsa","Mehus","Kuis","Tim","Tony","Yestgf","Pere"]
Years=[17,20,26,40,67,88,96,99,37]
Order=[1,2,3,4,5,6,7,8,9]

i am trying to extract data from it as follows
Jack Jack
Jack Jeni
Jack Monsa
Jack Mehus
Jack Kuis
Jack Tim
Jack Tony
Jack Yestgf
Jack Pere
Jeni Jeni
Jeni Monsa
Jeni Mehus
Jeni Kuis
Jeni Tim
Jeni Tony
Jeni Yestgf
Jeni Pere
Jeni Jack

and so on, for this i am writing a code as below

Names=["Jack","Jeni","Monsa","Mehus","Kuis","Tim","Tony","Yestgf","Pere"]
Years=[17,20,26,40,67,88,96,99,37]
Order=[1,2,3,4,5,6,7,8,9]
for names,years,orders in zip(Names,Years,Order):
   for i in range(1,(len(Order)+1)):
       for j in range(i,i+len(Order)):
           jdisplay = Names[j % len(Order)] if (j % len(Order)) else Names[j]
           print(names,Names[j])

i am getting following output

Quote:Traceback (most recent call last):
Jack Jeni
File "C:/Users/Administrator/PycharmProjects/Tesrt/forumsquestion.py", line 7, in <module>
Jack Monsa
Jack Mehus
Jack Kuis
Jack Tim
Jack Tony
Jack Yestgf
Jack Pere
jdisplay = Names[j % len(Order)] if (j % len(Order)) else Names[j]
IndexError: list index out of range

Process finished with exit code 1

It looks like i am doing everything wrong Cry

any help would be appreciated

RE: Accessing data in zip - Index out of range - Larz60+ - Mar-03-2018

I don't understand why the order and years lists are there,

Names=["Jack","Jeni","Monsa","Mehus","Kuis","Tim","Tony","Yestgf","Pere"]
# Years=[17,20,26,40,67,88,96,99,37]
# Order=[1,2,3,4,5,6,7,8,9]
# for names,years,orders in zip(Names,Years,Order):
#    for i in range(1,(len(Order)+1)):
#        for j in range(i,i+len(Order)):
#            jdisplay = Names[j % len(Order)] if (j % len(Order)) else Names[j]
#            print(names,Names[j])

for name in Names:
    for name1 in Names:
        print('{} {}'.format(name, name1))

RE: Accessing data in zip - Index out of range - buran - Mar-03-2018

or you can use itertools.product

from itertools import product
names=["Jack", "Jeni", "Monsa", "Mehus", "Kuis", "Tim", "Tony", "Yestgf", "Pere"]
for two_names in product(names, names):
    print(' '.join(two_names))

RE: Accessing data in zip - Index out of range - pythoneer - Mar-04-2018

(Mar-03-2018, 06:57 PM)Larz60+ Wrote: I don't understand why the order and years lists are there,

Names=["Jack","Jeni","Monsa","Mehus","Kuis","Tim","Tony","Yestgf","Pere"]
# Years=[17,20,26,40,67,88,96,99,37]
# Order=[1,2,3,4,5,6,7,8,9]
# for names,years,orders in zip(Names,Years,Order):
#    for i in range(1,(len(Order)+1)):
#        for j in range(i,i+len(Order)):
#            jdisplay = Names[j % len(Order)] if (j % len(Order)) else Names[j]
#            print(names,Names[j])

for name in Names:
    for name1 in Names:
        print('{} {}'.format(name, name1))

i actually want this to print in an order, it starts from Jack Jack and then 2nd set starts from Jeni Jeni, that is why i have used the order list

RE: Accessing data in zip - Index out of range - Larz60+ - Mar-04-2018

did you run what I gave you? Try it!

RE: Accessing data in zip - Index out of range - pythoneer - Mar-04-2018

(Mar-04-2018, 01:05 AM)Larz60+ Wrote: did you run what I gave you? Try it!

Yes, it didnt give me the output i was looking for Sad

part of that is as follows

Quote:Jack Jack
Jack Jeni
Jack Monsa
Jack Mehus
Jack Kuis
Jack Tim
Jack Tony
Jack Yestgf
Jack Pere
Jeni Jack
Jeni Jeni

See where the 2nd set starts :(

RE: Accessing data in zip - Index out of range - Gribouillis - Mar-04-2018

Simpler is better:

names=["Jack","Jeni","Monsa","Mehus","Kuis","Tim","Tony","Yestgf","Pere"]
for i, a in enumerate(names):
    for b in names[i:] + names[:i]:
        print(a, b)

RE: Accessing data in zip - Index out of range - pythoneer - Mar-04-2018

(Mar-04-2018, 06:41 AM)Gribouillis Wrote: Simpler is better:

names=["Jack","Jeni","Monsa","Mehus","Kuis","Tim","Tony","Yestgf","Pere"]
for i, a in enumerate(names):
    for b in names[i:] + names[:i]:
        print(a, b)

it starts to malfunction if we go a bit deeper

names=["Jack","Jeni","Monsa","Mehus","Kuis","Tim","Tony","Yestgf","Pere"]
for i, a in enumerate(names):
    for b in names[i:] + names[:i]:
        for c in names[i:] + names[:i]:
            for d in names[i:] + names[:i]:
                print(a, b, c, d)

Quote:Jack Jack Jack Jack
Jack Jack Jack Jeni
Jack Jack Jack Monsa
Jack Jack Jack Mehus
Jack Jack Jack Kuis
Jack Jack Jack Tim
Jack Jack Jack Tony
Jack Jack Jack Yestgf
Jack Jack Jack Pere
Jack Jack Jeni Jack
Jack Jack Jeni Jeni

RE: Accessing data in zip - Index out of range - buran - Mar-04-2018

if I get right your ever-changing goal, you just need to have similar construct with enumerate for every loop but the last one

RE: Accessing data in zip - Index out of range - pythoneer - Mar-04-2018

(Mar-04-2018, 07:34 AM)buran Wrote: if I get right your ever-changing goal, you just need to have similar construct with enumerate for every loop but the last one

:( sorry, i dont get you ,can you please show me the code