Beginner Q: failure to find string in list - Printable Version +- Python Forum (https://python-forum.io) +-- Forum: Python Coding (https://python-forum.io/forum-7.html) +--- Forum: General Coding Help (https://python-forum.io/forum-8.html) +--- Thread: Beginner Q: failure to find string in list (/thread-9032.html) |
Beginner Q: failure to find string in list - Jenny - Mar-18-2018 I am a total beginner, so likely to be missing something obvious here. First post so be kind! print('Looking for ', Name_key, 'in', headerList) Name_listIndex = headerList.index(Name_key)The print function acts out exactly as I expect, giving me confidence that my variables are correctly set: >>> Looking for ['IAU Name'] in ['IAU Name', 'Designation', 'ID', 'Const.', '#', 'WDS_J', 'Vmag', 'RA(J2000)', 'Dec(J2000)', 'Approval Date'] Next I expected it to set Name_listIndex to match the index at which Name_key is found in headerList. So I was expecting it to set Name_listIndex = 0. Instead I get: >>> ValueError: ['IAU Name'] is not in list It works fine using a dummy list and key variable, just not with the real data. I am too confused. Thanks for any support! Jenny RE: Beginner Q: failure to find string in list - snippsat - Mar-18-2018 You are looking for list ['IAU Name'] ,but in list it's a string 'IAU Name' .>>> lst = ['IAU Name', 'Designation', 'ID', 'Const.', '#', 'WDS_J', 'Vmag', 'RA(J2000)', 'Dec(J2000)', 'Approval Date'] >>> name = ['IAU Name'] >>> if name in lst: ... print('True') ... lst.index(name) ... >>> name = 'IAU Name' >>> if name in lst: ... print('True') ... lst.index(name) ... True 0 RE: Beginner Q: failure to find string in list - Jenny - Mar-18-2018 Awesome thank you. |