IndexError: tuple index out of range

IndexError: tuple index out of range - Printable Version

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IndexError: tuple index out of range - Truman - Mar-25-2018

tp=(1,2,3,4,5,6,7,8,9,10)
for i in tp:
    lt = []
    if tp[i]%2 == 0:
        lt.append(tp[i])
    else:
	    pass
tp2 = tuple(lt)
print(tp2)

I don't understand why is i out of range.

After change in code I receive the same message

tp=(1,2,3,4,5,6,7,8,9,10)
for i in tp:
    lt = []
    for i in range(1,11):
        if tp[i]%2 == 0:
            lt.append(tp[i])
        else:
	        pass
tp2 = tuple(lt)
print(tp2)

RE: IndexError: tuple index out of range - woooee - Mar-26-2018

What is the complete error message which shows which line the error is on? Print i right after the for i in tp, and then print tp[i], which will error, so print on a separate line. You don't want 2 statements here as the for i in tp is already accessing the values in tp. There are additional problems in the next for i in tp, but that is for you to figure out.

RE: IndexError: tuple index out of range - wavic - Mar-26-2018

Because you are using the values from the tuple as an index to the elements in the same tuple.
tp contains 10 elements. But tp[10] is the 11th element ( indexing starts from 0 ) and of course, it doesn't exist.

Change the if statement.

if i % 2 == 0:
    lt.append(i)

In the first code snippet.

RE: IndexError: tuple index out of range - Truman - Mar-26-2018

wavic, the output is now (10,)

(Mar-26-2018, 12:50 AM)woooee Wrote: What is the complete error message which shows which line the error is on? Print i right after the for i in tp, and then print tp[i], which will error, so print on a separate line. You don't want 2 statements here as the for i in tp is already accessing the values in tp. There are additional problems in the next for i in tp, but that is for you to figure out.

tp=(1,2,3,4,5,6,7,8,9,10)
for i in tp:
    print(i)
    print(tp[i])
    lt = []
    if i%2 == 0:
        lt.append(i)
    else:
        pass
tp2 = tuple(lt)
print(tp2)

it gives line 4

RE: IndexError: tuple index out of range - wavic - Mar-27-2018

Again, do not use the values as an index!

How the output is (10,)? What have you tried exactly?

Here is the same code. You can skip the else statement.

>>> lt = []
>>> tp = (1, 2, 3, 4, 5, 6, 7, 8, 9, 10)
>>> for i in tp:
...     if i % 2 == 0:
...         lt.append(i)
...     else:
...         pass
... 
>>> tp2 = tuple(lt)
>>> print(tp2)
(2, 4, 6, 8, 10)

I see now that your lt = [] is inside the for loop. So on every iteration you wipe it out to an empty list

RE: IndexError: tuple index out of range - Truman - Mar-27-2018

lt = []
tp=(1,2,3,4,5,6,7,8,9,10)
for i in tp:
    
    if i%2 == 0:
        lt.append(i)
   
tp2 = tuple(lt)
print(tp2)

Now it works and I completely understand it. Thank you.