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Search Results
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Thread: queued music wont play, how to do this?
Post: queued music wont play, how to do this?
| queued music wont play next, any idea on this?
import pygame
import time
pygame.mixer.init()
pygame.mixer.music.load('goodbye.ogg')
pygame.mixer.music.play(1)
time.sleep(1.08)
pygame.mixer... |
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glennford49 |
General Coding Help |
0 |
1,389 |
Nov-24-2020, 12:54 PM |
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Thread: broadcasting euclidean distance error
Post: broadcasting euclidean distance error
| i have this code, i tried to calculate euclidean distance on each element on list1
it throws an error if list1 has 2 elements, any idea on this?
import numpy as np
from scipy.spatial import distance
... |
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glennford49 |
General Coding Help |
1 |
4,005 |
Nov-12-2020, 11:26 AM |
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Thread: extracting second values elements only in every keys in an OrderedDict
Post: RE: extracting second values elements only in ever...
| thanks, +1, this saves my day |
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glennford49 |
General Coding Help |
4 |
2,523 |
Nov-12-2020, 08:22 AM |
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Thread: extracting second values elements only in every keys in an OrderedDict
Post: extracting second values elements only in every ke...
| i have this code, i want to extract the second values elements only in every keys in an OrderedDict,
i dont want to use for loop,any idea on this ?
from collections import OrderedDict
regDict= Order... |
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glennford49 |
General Coding Help |
4 |
2,523 |
Nov-11-2020, 12:35 PM |
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Thread: making list in looping a dictionary
Post: RE: making list in looping a dictionary
| (Jun-25-2020, 12:55 PM)deanhystad Wrote: Do you want a list of the dictionary keys, or do you want a list that contains the dictionary as a list? Should the end result look like this:
["glenn","ele... |
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glennford49 |
General Coding Help |
9 |
3,580 |
Jun-25-2020, 02:32 PM |
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Thread: making list in looping a dictionary
Post: RE: making list in looping a dictionary
| i dont know what is the correct approach , for each loop or for i, i dont have any idea,
all i need is to loop the dictionary to get each keys as list item
users={"glenn":1,"elena":2,"mama":3}
names=... |
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glennford49 |
General Coding Help |
9 |
3,580 |
Jun-25-2020, 10:18 AM |
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Thread: making list in looping a dictionary
Post: RE: making list in looping a dictionary
| im using a dictionary instead of manually writing the list out of names , coz each values and keys has purpose on another script and i want that if I add values and keys in that dictionary, list item ... |
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glennford49 |
General Coding Help |
9 |
3,580 |
Jun-25-2020, 09:54 AM |
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Thread: making list in looping a dictionary
Post: making list in looping a dictionary
| how to make a list out of this ?
is this the right approach?
users={"glenn":1,"elena":2,"mama":3}
names=(list(users.keys()))
for i in names:
# i should become a list of each 3 keys in a dictionay
... |
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glennford49 |
General Coding Help |
9 |
3,580 |
Jun-25-2020, 09:34 AM |
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Thread: How to do this kind of IF STATEMENT?
Post: RE: How to do this kind of IF STATEMENT?
| (Jun-16-2020, 12:55 PM)buran Wrote: or even better
if any(pins):
print('true')
else:
print('none')
thanks for this, it seems easier. +1 |
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glennford49 |
General Coding Help |
4 |
2,645 |
Jun-17-2020, 09:45 AM |
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Thread: How to do this kind of IF STATEMENT?
Post: RE: How to do this kind of IF STATEMENT?
| (Jun-16-2020, 11:55 AM)menator01 Wrote: p1=1
p2=0
p3=0
p4=0
pins=[p1,p2,p3,p4]
for value in pins:
if value == 1:
print("true")
else:
print("none")Output:true
none
none
none
... |
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glennford49 |
General Coding Help |
4 |
2,645 |
Jun-16-2020, 12:33 PM |
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Thread: How to do this kind of IF STATEMENT?
Post: How to do this kind of IF STATEMENT?
| How to do this kind of IF STATEMENT?
p1=1
p2=0
p3=0
p4=0
pins=[p1,p2,p3,p4]
for i in pins:
if (pins has value==1)
print("true")
else:
print("none")
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glennford49 |
General Coding Help |
4 |
2,645 |
Jun-16-2020, 10:54 AM |
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Thread: NameError: name 'pins' is not defined
Post: RE: return a function error
| (Jun-15-2020, 12:00 PM)buran Wrote: result_names = 'elena'
dict={"glenn":1,"elena":2}
def person(names):
pins =dict.get(names)
return pins
pins = person(result_names)
print(pins)you ne... |
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glennford49 |
General Coding Help |
2 |
3,603 |
Jun-15-2020, 12:20 PM |
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Thread: NameError: name 'pins' is not defined
Post: NameError: name 'pins' is not defined
| NameError: name 'pins' is not defined
result_names = 'elena'
dict={"glenn":1,"elena":2}
def person(names):
pins =dict.get(names)
return pins
person(result_names)
print(pins)im trying to get th... |
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glennford49 |
General Coding Help |
2 |
3,603 |
Jun-15-2020, 11:50 AM |
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Thread: using element on a list as condition statement
Post: RE: using element on a list as condition statement
| (May-19-2020, 09:15 AM)menator01 Wrote: sum = 33
list1=[11,22,33,44,55]
if sum in list1:
print(f'{sum} is in list')
else:
print(f'{sum} is not in list')Output:33 is in listthanks for the qui... |
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glennford49 |
General Coding Help |
11 |
5,006 |
May-19-2020, 09:31 AM |
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Thread: using element on a list as condition statement
Post: using element on a list as condition statement
| how to implement this code ?
i want any value in the list1 be compared in variable sum
if has , statements will follow
if no , prints a string as stated below
sum = 33
list1=[11,22,33,44,55]
if (su... |
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glennford49 |
General Coding Help |
11 |
5,006 |
May-19-2020, 09:07 AM |
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Thread: count each element in a list
Post: RE: count each element in a list
| (May-01-2020, 11:09 AM)anbu23 Wrote: (May-01-2020, 10:50 AM)glennford49 Wrote: how to return the exact same element found in list2?
Remove len()
thumbs up, this saves my day! |
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glennford49 |
General Coding Help |
9 |
4,027 |
May-01-2020, 11:20 AM |
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Thread: count each element in a list
Post: RE: count each element in a list
| (May-01-2020, 10:47 AM)pyzyx3qwerty Wrote: (May-01-2020, 10:45 AM)glennford49 Wrote: it returns nothing since list2 has no same item from list1 it has only 3 same elements that which i want to be ... |
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glennford49 |
General Coding Help |
9 |
4,027 |
May-01-2020, 10:50 AM |
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Thread: count each element in a list
Post: RE: count each element in a list
| (May-01-2020, 10:34 AM)pyzyx3qwerty Wrote: If you want to print the same element in both lists, you can do:
for i in list1 :
if i in list2 :
#your codeit returns nothing since list2 has ... |
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glennford49 |
General Coding Help |
9 |
4,027 |
May-01-2020, 10:45 AM |
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Thread: count each element in a list
Post: RE: count each element in a list
| Thanks for your response,len() just return number of item in list2 which is 2, i want if there is/are same element on each item from list2 will be printed, using list1 as comparison |
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glennford49 |
General Coding Help |
9 |
4,027 |
May-01-2020, 10:37 AM |
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Thread: count each element in a list
Post: count each element in a list
| hi guys , i want to print same element in each item in a list,
my code returns nothing except if i print list2,
it should return 3 elements in first item and 2 elements in a second one
list1=[10,... |
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glennford49 |
General Coding Help |
9 |
4,027 |
May-01-2020, 09:37 AM |
