Noob help :)

[rwood1875]

Hi all. I'm getting an error message when running the following code.
I'm assuming its something to do with integers not being strings and vice-versa.

User chooses whether the 10 passwords to be generated should be made from Upper/Lower/Mixed chars.

import string

from random import *

generated = 0
min_char = 8
max_char = 12
optionchar = 0
chosenchar = ""

while optionchar != '1' and optionchar != '2' and optionchar != '3':
    print('Choose the string type for the password:')
    print('1 - lowercase')
    print('2 - UPPERCASE')
    print('3 - MiXeDcAsE')
    optionchar = input()


print('You chose ' + str(optionchar))


if optionchar == 1:
    chosenchar == str(string.ascii_lowercase)
if optionchar == 2:
    chosenchar == str(string.ascii_uppercase)
if optionchar == 3:
    chosenchar == str(string.ascii_letters)



while generated <10:
    password = "".join(choice(str(chosenchar)) for x in range(randint(min_char, max_char)))
    print ("This is your password: ",password)
    generated = generated + 1

thank you

[j.crater]

You are correct

optionchar = input()

At this point optionchar is a string, so you can do something like:

optionchar = int(input())

In future when you are not sure, simply use print for debugging. If you want to know a type of a variable, you can print it with:

print(type(optionchar))

Edit:

Unless there some other purpose I don't see, you don't even need to convert input to integer, if you simply compare to string in the first place:

if optionchar == '1':

[rwood1875]

Thank you, that worked.