Finding value in nested dictionaries with lists

[ibreeden]

Hello Mart79,
No, that is not what I mean. I meant this:

from collections import OrderedDict # the data appears to contain an OrderedDict.

def recurse_object(obj_to_inspect, val_to_find, indexpath=""):
    if isinstance(obj_to_inspect, dict):
        for key, value in obj_to_inspect.items():
            recurse_object(value, val_to_find, indexpath + f"['{key}']")
    if isinstance(obj_to_inspect, list):
        for key, value in enumerate(obj_to_inspect):
            recurse_object(value, val_to_find, indexpath + f"[{key}]")
    if isinstance(obj_to_inspect, str):
        if obj_to_inspect == val_to_find:
            print(f"Value {val_to_find} found at {indexpath}")

dictionary = {'nestedA': OrderedDict([('Name', 'TestCase'), ('VarA', 'Local'), ('VarB', None), ('VarC', None), ('VarD', [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]), ('VarE', 'ABCD'), ('VarF', 10.0), ('VarG', False)]), 'nestedB': OrderedDict([('LocA', {'v1': 'ABCD', 'v2': None, 'v3': None, 'v4': [[[0, 1], [1, 1], [2, 2], [0, 4]], [[0, 2], [1, 2], [2, 3], [4, 4]], ['name', 'ABCD']]}), ('LocB', None), ('LocC', None), ('LocD', True), ('LocE', True), ('LocF', False), ('LocG', False)])}
recurse_object(dictionary, 'ABCD') 

Output:
Value ABCD found at ['nestedA']['VarE']
Value ABCD found at ['nestedB']['LocA']['v1']
Value ABCD found at ['nestedB']['LocA']['v4'][2][1]

By the way: You used dict = {'nestedA': ... etc. Never use reserved words (like dict) as a name of a variable.