Calculate the multiple of a number

[ibreeden]

I want to optimize it. I have these two lines print(i,r) and return(r ). Is there a way I can get rid of one of these two lines and yet have the correct output giving only the multiple of a number ?

# -*- coding: utf-8 -*-
# Les nombre multiples de n compris entre 1 et 60
def multiple(n):
    return int(60/n)

print(multiple(15))

Output:
4