Regex: finding if three groups have a value in them

[Daring_T]

Hello, I have started learning python via documentation & videos because I trying to make a program that converts episode number and timestamps in a .txt to an XML chapter file.

Write now I am trying to take the raw episode raw format and output 1 or 2 numbers and groups 6 is giving me There was no Match when it should be saying 6 is a match. I don't know if I`m going about this the right way, so any s or suggestions would be great.

import re
Input = 'd7 23'
###Input should output 23 via groups 2 or 3 or 6 

##Input = '23'
##Input = 'ep23'
ep_regex = '((?i)EP(\d\d?))?(^\d\d?$)?(((?i)d\w[\s|:])?(\d\d?))?'
ep_prog = re.compile(ep_regex) 
ep_result = ep_prog.match(Input)

one = ep_result.group(1)
two = ep_result.group(2)
three = ep_result.group(3)
four = ep_result.group(4)
five = ep_result.group(5)
six = ep_result.group(6)

if two or three or six is True:
    if two == None:
        print('No match in G2')
        pass
    else:
        print('2 is a Match!')
    if three == None:
        print('no match in G3')
        pass
    else:
        print('3 is a Match!')
    if six == None:
        print('No Match in G6')
        pass
    else:
        print ("6 is a match!")        
else:
    print("There was no Match")
print('group 1 -->',one)
print('group 2 -->',two)
print('group 3 -->',three)
print('group 4 -->',four)
print('group 5 -->',five)
print('group 6 -->',six)

Here`s the error that I WAS getting if that helps.

Error:
Warning(from warnings module):
  File "C:\Users\new user\Desktop\py read & replace\Regex_Examples\ep_re_group_match.py", line 9
    ep_prog = re.compile(ep_regex)
DeprecationWarning: Flags not at the start of the expression '((?i)EP(\\d\\d?))?(^\\d' (truncated)