Regex: finding if three groups have a value in them

[Daring_T]

Thanks Brian and Deanhystad for the help I did not know it was that simple.

Here`s the fixed code for the people surfing on the forms ;)

import re
Input = 'd7 23'
###Input should output 23 via groups 2,3,6 
##Input = '23'
##Input = 'ep23'
ep_regex = '((i?)EP(\d\d?))?(^\d\d?$)?(((i?)d\w[\s|:])?(\d\d?))?'
ep_prog = re.compile(ep_regex) 
ep_result = ep_prog.match(Input)

#zero = (ep_result.group(0))
one = ep_result.group(1)
two = ep_result.group(2)
three = ep_result.group(3)
four = ep_result.group(4)
five = ep_result.group(5)
six = ep_result.group(6)

if two or three or six:
    if two == None:
        pass
    else:
        print('Your Episode number is: %s' % (two))
    if three == None:
        pass
    else:
        print('Your Episode number is: %s' % (three))
    if six == None:
        pass
    else:
        print('Your Episode number is: %s' % (six))
else:
    print("There was no Match")