else condition not called when if condition is false

[deanhystad]

Answer is the same though. When the guess is not in the list index throws an exception.

There is no reason the word can't be a string. The word doesn't change. Here's a "Wheel of Fortune" version of Hangman. It matches multiple positions if a letter occurs in the word more than once.

import random

def find_all(letter, word):
    """Return array of indices where letter appears in word"""
    return [i for i, x in enumerate(word) if x == letter]

def hangman(word):
    """Play a game of hangman"""
    # Initialize to empty board
    word = word.upper()
    count = len(word)
    letters = ['_']*count
    remaining = count
    misses = 0

    # Begin play.  Play continues until player guesses the word or runs out of misses
    while remaining > 0 and misses < 6:
        """Draw the letters and remaining misses.  Get letter guess"""
        print(' '.join(letters))
        letter = input(f'Misses = {misses}.  Enter letter: ').upper()

        """Find all matches"""
        matches = find_all(letter, word)
        if len(matches) == 0:
            misses += 1  # No match
        else:
            for i in matches:
                letters[i] = letter # Replace blanks with letter
            remaining -= len(matches)

    # Did they win?
    if remaining == 0:
          print('Congratulations!')
    print(f'The word was "{word}"\n')
        

# Allow for multiple plays
words = ['Orangatan', 'Hippopotomus', 'Giraffe', 'Cheetah', 'Chimpanzee']
random.shuffle(words)

# Play until out of words or the player wants to quit.
first = True
for word in words:
    if not first:
        if input('Would you like to play again? ').upper()[0] != 'Y':
              break
    first = False
    hangman(word)