print only last matched line

[tester_V]

Here is the code.
It prints all lines (the ones I'm looking for) but I do not need all lines.
I need to print only the last match of "the second line that is LotComplete" for each "first line that is -- InitializeRequest ".
Do you know how to do that?

Thank you.

import os
import re

lstr = '-- InitializeRequest'
lt_nd = '-- LotComplete'
ltend = ''
hand_f = '\\somelog.txt'

with open(hand_f) as apse:
    for rn_l in apse:
        rn_l= rn_l.rstrip()
        #print (rn_l)
        if lstr in rn_l :
            #print (rn_l)
            rn_l = rn_l.replace('[','').replace(']','')  
            st1,*extraWords, = rn_l.split('-')  
            print ("Lot Start-->> ", st1,'\n')       
          
            
        if lt_nd in rn_l :
            rn_l = rn_l.replace('[','').replace(']','')
            st2,*extraWords, = rn_l.split('-') 
            print("LotComplete -->> ", st2, '\n')