C to Python code conversion print problem

[anakk1n]

Hello! I need to convert this C code I made to Python:
https://gist.github.com/anakk1n/dadf2216...10c3839af5

My python code looks like this:

def algoritm2(v, n, d, c):
    p = 0
    j = -3
    k = 0
    for i in range(n-1):
        if (j >= n - 2):
            break
        if (p == 1):
            print(v[j+1], " ", end='')
            u = k = v[j + 1]
            i = j + 1
            c = c + 1
            p = 0
        else:
            u = -1
        j = i
        aux = v[i] + d + 1
        if (aux <= v[i + 1] and u == -1):
            print(v[i], " ", end='')
            k = v[i]
            c = c + 1
        else:
            if (((v[i] - v[i - 1] >= d) and u != v[i]) or (i == 0)):
                k = v[i]
                print(v[i], " ", end='')
                c = c + 1
            while (aux > v[j + 1] and j < n - 2):
                j = j + 1
                p = 1
    if (v[n - 1] - k >= d + 1):
        print(v[n-1], " ", end='')
    return c

Problem is that it doesn't list 100% the same thing. Did i do anything wrong in the conversion? Also, I changed the 'l' variable in the C code with the 'c' variable in python and in Python I made it return 'c', but it shouldn't affect my result