Counting vowels in a string (PyBite #106)

[Drone4four]

you need to iterate over chars in text and check if char is in vowels

Thank you, my friend!

Here is my script now:

vowels = 'aeiou'
# vowels = ('a', 'e', 'i', 'o', 'u')
result = 0
for char in text:
    if char.lower() in vowels:
        result = result +1
print(result)

The output is exactly: 262. I did it!

I just wish I could have come up with this on my own instead of having to write a long winded, overly analytical question when the solution was so clearly obvious.

Thanks again, @buran.