Leap Year

[wavic]

Hello!
Put print() in each loop to see where it returns True.

For the year 2400, this will happen in the first loop because 2400 % 4 == 0 is True and will print that this year leap.

Change the conditions

def get_year():
   print("Please input year:")
   year = int(input())
   return year
 
def if_else(year):
   if year % 4 == 0 and year % 100 != 0:
     print("It's a leap year")
   elif year % 400 == 0 and year % 100 != 0:
     print("It's a leap year")
   elif (year % 100 == 0):
     print("It's not a leap year")
   else:
     print("There is an error")
 
def main():
   years = get_year()
   if_else(years)

Or put if year % 100 ==0: on top

Also, if one enter something that cannot be converted to in like text for example the script will stop with ValueError