Search Results Web results Printing the number of days in a given month and year

[afefDXCTN]

Hi everybody!

I wrote this code to return the number of days for a given couple of months / day
my function must take into consideration leap years for the calculation of the number of days in the month of February
So my function should return none if the arguments don't make sense

This is the code

def isYearLeap(year):
    return year % 4 == 0 and (year % 400 == 0 or year % 100 != 0)

def daysInMonth(year, month):
   if month in ['September', 'April', 'June', 'November']:
        print 30

    elif month in ['January', 'March', 'May', 'July', 'August','October','December']:
        print 31        

    elif month == 'February' and isYearLeap(year) == True:
        print 29

    elif month == 'February' and isYearLeap(year) == False:
        print 28

    else:
        return None
testYears = [1900, 2000, 2016, 1987]
testMonths = [2, 2, 1, 11]
testResults = [28, 29, 31, 30]
for i in range(len(testYears)):
	yr = testYears[i]
	mo = testMonths[i]
	print(yr, mo, "->", end="")
	result = daysInMonth(yr, mo)
	if result == testResults[i]:
		print("OK")
	else:
		print("Failed")[/quote]

NB:
at the beginning I did not enter the parentheses for the number of days (30/31/29/28) for the print function, I had this error
File "main.py", line 6
print 30
^
SyntaxError: Missing parentheses in call to 'print'. Did you mean print (30)?

*********************************


then I add the parentheses and I got this error
File "main.py", line 8
elif month in ['January', 'March', 'May', 'July', 'August', 'October', 'December']:


Can you help me please, how can i solve this issue??