shuffle a nested list

[perfringo]

Because i am confused shouldnt that code return the emptylist with 8 shuffled differenlty sublists?

No, it shouldn't. There is only one list and you shuffle it 8 times.

Maybe following code can explain:

>>> nums = [1, 2, 3]
>>> emptylist = []
>>> for i in range(3):
...     emptylist.append(nums)     # you are adding same list n times
...
>>> emptylist
[[1, 2, 3], [1, 2, 3], [1, 2, 3]]
>>> for item in emptylist:
...     print(id(item))
...
140256603923232                    # same object 3 times
140256603923232                    # or more correctly three references to same object
140256603923232
>>> emptylist[0][0] = 'no way'     # changing item in emptylist
>>> emptylist                      # changes all items because they reference same object 
[['no way', 2, 3], ['no way', 2, 3], ['no way', 2, 3]]   
>>> nums[1] = "it's happening"     # it's getting worse; you change original list
>>> emptylist                      # and as this is same object it is reflected in emptylist
[['no way', "it's happening", 3],
 ['no way', "it's happening", 3],
 ['no way', "it's happening", 3]]