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function giving different result with @functool.cache
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function giving different result with @functool.cache
#4
(Nov-23-2020, 04:52 PM)deanhystad Wrote:
        prerow = [1].append(prerow)  # Makes a new list.  Fixes shared list problem.
        for i in range(1, len(prerow) - 1):
            prerow[i] += prerow[i+1]
        return prerow
you mean this:
one = [1]
one.extend(prerow)
prerow = one
for i in range(1, len(prerow)-1):
    prerow[i] += prerow[i+1]
return prerow
or even better I guess:
prerow = prerow.copy()
for i in range(len(prerow)-1):
    prerow[i] += prerow[i+1]
return [1] + prerow
It is now obvious where I fucked up. thx. "Make a new list" this helped.
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Messages In This Thread
RE: function giving different result with @functool.cache - by naughtysensei - Nov-25-2020, 03:12 PM

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