Play again, in a guessing game

[banidjamali]

Hello!

Here the computer comes up with a number in range(1, 9), and we try to guess it, until we come up with the correct number.
We can exit anytime during the game and also at the end we have the choice to play again.

import random
def guessing():
    computer = random.randint(1, 9)
    number_of_guesses = 0
    while True:
        number_of_guesses += 1
        pick = input("Guess, if you dare: ")
        if pick.lower() == "exit":
            print("Better luck next time!")
            print("Attempts:", number_of_guesses - 1)
            break
        elif int(pick) > computer:
            print("Too high.")
        elif int(pick) < computer:
            print("Too low.")
        elif int(pick) == computer:
            print("Yes!")
            if number_of_guesses == 1:
                print("Are you God?!")
            elif number_of_guesses < 3:
                print(f"Impressive! Only {number_of_guesses} attemps.")
            else:
                print(f"Finally! After {number_of_guesses} attemps.")
            break
    again()

def again():
    if input("Continue?(y/n) ") == 'y':
        guessing()
    else:
        exit

guessing()

I've been told that I don't need to define a separate function for just asking the user if they want to play again. But I can't seem combine the two functions together.

Thank you for reading.