Feb-04-2021, 07:18 AM
You're asking a bit too much. 
When i plan to make an app like, 4-in-a-row, blackjack, Texas hold'm, even swiss pairing,
i know that there are many people who published a solution for that.
I never look at those, because (a), there is no fun in it, (b) by the time you figured out what
somebody else has done, you may have done it yourself.
I will elaborate on my matches idea:
Three players: A, B, C (license numbers as you call them)
A against B, A starts with white : 'A-B', if B starts with white 'B-A'.
You can easily check if 'A against B' has already been played with the "in list" function.(or B-A as well)
You can tell how many times A had white, by counting the number of 'A-x'' in the list.
You can count the number of matches A played. (black + white distinctive)
You can also tell who A did not play.
You can link A directly to your dictionary.
Still in the same list, if you want to show who won, you can do 'a-B', 'B-c' if your licence numbers have a string in them.
Limitless really...
Paul
When i plan to make an app like, 4-in-a-row, blackjack, Texas hold'm, even swiss pairing,
i know that there are many people who published a solution for that.
I never look at those, because (a), there is no fun in it, (b) by the time you figured out what
somebody else has done, you may have done it yourself.
I will elaborate on my matches idea:
Three players: A, B, C (license numbers as you call them)
A against B, A starts with white : 'A-B', if B starts with white 'B-A'.
You can easily check if 'A against B' has already been played with the "in list" function.(or B-A as well)
You can tell how many times A had white, by counting the number of 'A-x'' in the list.
You can count the number of matches A played. (black + white distinctive)
You can also tell who A did not play.
You can link A directly to your dictionary.
Still in the same list, if you want to show who won, you can do 'a-B', 'B-c' if your licence numbers have a string in them.
Limitless really...
Paul