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[solved] Variable number of dictionnaries as argument in def()
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[solved] Variable number of dictionnaries as argument in def()
#5
as mentioned by @ndc85430 it is unclear what are you actually trying to achieve

maybe something like this?
from itertools import chain
spam = {'foo':1, 'bar':2}
eggs = {'x':0, 'y':3}

dicts = [spam, eggs]

def get_keys(*args):
    for some_dict in args:
        print(list(some_dict.keys()))

def get_keys2(*args):
    print(list(chain(*args)))

get_keys(*dicts)
get_keys2(*dicts)
Output:
['foo', 'bar'] ['x', 'y'] ['foo', 'bar', 'x', 'y']
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Messages In This Thread
RE: Variable number of dictionnaries as argument in def() - by buran - Apr-19-2021, 05:18 PM

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