[solved] Variable number of dictionnaries as argument in def()

[paul18fr]

At least for such intent, I guess I figured out

Thanks

import numpy as np
from itertools import chain

# A dictionnary is created
n = 10
m = 1
X = np.random.random( (n,m) )
Y = np.random.random( (n,m) )
Z = np.random.random( (n,m) )
MyDictionnary = {'Abcissa': X, 'Ordinate': Y, 'Altitude': Z}
MyDictionnary2 = {'Abcissa2': X, 'Ordinate2': Y, 'Altitude2': Z, 'Theta': (X+Y)}
del X, Y, Z

# # Dictionnary keys are listed / the dictionnary is explicitly expressed
KeyList0 = list(MyDictionnary.keys())
print("Key list (explicitly) : {}".format(KeyList0))


## function get keys lists
def DictionnaryTest(*args):
    return(list(chain(*args)))

# A list of dictionnary names is now created
DictionnaryNamesTable = [MyDictionnary, MyDictionnary2]

KeyList2 = DictionnaryTest(*DictionnaryNamesTable)
print("Key list2 : {}".format(KeyList2))


## list composed of a single dictionnary
DictionnaryNamesTable = [MyDictionnary]
KeyList1 = DictionnaryTest(*DictionnaryNamesTable)
print("Key list1 : {}".format(KeyList1))