Regex - Pass Flags as a function argument?

[muzikman]

Can you please remove the phone numbers from your post. They are real phone numbers. I forgot to remove them before posting.

Thanks.

Like this,so if look regex source code they do same with flags=0.
This is kind of double up just use the search function

import re

def search(pattern, string, flags=0):
    result = re.search(pattern, string, flags) # I want to pass these as an argument to the 'search' function.
    if result is None:
        return None
    else:
        return result

if __name__ == '__main__':
    string = "This is a string with two phone numbers "
    pattern = r"\d{3}-\d{3}-\d{4}"
    flags = re.VERBOSE | re.IGNORECASE
    result = search(pattern, string, flags)
    print(result)

The argument given has to be same format then get parsing | for free.
Them do some magic to join | in parameter,just to take out 2 lines.

res = '|'.join(members)
globals().update(RegexFlag.__members__)