Dynamic File Name to a shared folder with open command in python

[DeaD_EyE]

And I have to turn the generator into a list to get the length

We need len_consume :-D

import pathlib


# this works
unc1 = pathlib.PureWindowsPath(r"\\host\share\file1")

# this seems to work also
unc2 = pathlib.PureWindowsPath(r"\\host\share") / "file1"

# the pathlib has support for unc paths, but only if the full path to the share is used
# concatenating the host part with share part will not work.

unc3 = pathlib.PureWindowsPath(r"\\host") / "share/dir/file"


print("OK", unc1)
print("OK", unc2)
print("FAIL", unc3)

Output:
OK \\host\share\file1
OK \\host\share\file1
FAIL \host\share\dir\file

I used PureWindowsPath because I'm on a Linux system.

For my understanding, it is important, that the str itself has the right format.

This is ok:

print(r"\\host\share\file1")

Output:
\\host\share\file1

This is not ok:

print("\\host\share\file1")

Output:
\host\share
ile1

The first \ escapes the second backslash, if a raw string literal is not used.
The \f is the control character Form Feed.

Working with backslashes in string literals without the r-prefix, will cause problems.

The second important thing for UNC paths is, that they must supply in following structure: \\host\share.