How to access previous row using itertuples

[perfringo]

One way is to access rows by indices. Of course, there is still question about first row - whether it should be ignored or what?

import numpy as np
import pandas as pd

df = pd.DataFrame(np.arange(35).reshape(7, 5), columns=[*'abcde'])

for i in range(1, df.shape[0]):
    print("Current row", *df.iloc[i])
    print("Previous row",  *df.iloc[i-1])

Output:
Current row 5 6 7 8 9
Previous row 0 1 2 3 4
Current row 10 11 12 13 14
Previous row 5 6 7 8 9
Current row 15 16 17 18 19
Previous row 10 11 12 13 14
Current row 20 21 22 23 24
Previous row 15 16 17 18 19
Current row 25 26 27 28 29
Previous row 20 21 22 23 24
Current row 30 31 32 33 34
Previous row 25 26 27 28 29

I am not motivated enough to find out whether its faster than itertuples and getattr. I also believe that print is not the objective as I can't see any value of printing out 20K rows.