Calculator Help..?

[Josh]

You can use an exception to achieve this.

With the code that you have used, I would do this.

print("Select An Operator")
print("Addition:        +")
print("Subtraction:     -")
print("Multiplication:  *")
print("Division:        /")

operator = input("Enter Choice (+,-,*,/:) ")

number = int(input("Please enter a number: "))
number2 = int(input("Please enter a second number: "))

try:
 if operator == '+':
     print(number + number2)
 elif operator == '-':
     print(number - number2)
 elif operator == '*':
     print(number * number2)
 elif operator == '/':
     print(number / number2)
 else: print("ERROR!")
except: print("ERROR!")

This code will "try" to do the task, and will output "ERROR" if an error is returned as we have used an exception.

If I was writing a calculator, I would just write something like this:

try:print(eval(input("Enter the equation")))
except:print("Error")

It takes input like 5*3, evaluates it and outputs the result. If there is an error in the process, "Error" will be outputted.

I hope this helps!