How to fix list index out of range

[deanhystad]

Is this correct?

        Node_Start = Node(S, [6, 3, 1, 1])
        Node_3 = Node(3, [7, 4, 1, S])

It think your board is still riddled with errors. You would be better off making the wall programmatically. You make too many mistakes when doing it by hand.

This is how I make my board. I use dictionaries instead of arrays

class Action(Enum):
    """Enumeration for movements (actions). Value is (row, column) steps to make move"""
    UP = (1, 0)
    RIGHT = (0, 1)
    DOWN = (-1, 0)
    LEFT = (0, -1)

    def __str__(self):
        """Return arrow associated with action""""
        if self is self.LEFT:
            return '\u2190'
        elif self is self.UP:
            return '\u2191'
        elif self is self.RIGHT:
            return '\u2192'
        elif self is self.DOWN:
            return '\u2193'
        return " "

class Board:
    def __init__(self, goals, traps, walls, rows=4, columns=4):
        """Initialize the board"""
        # Make all the tiles
        self.rows = rows
        self.columns = columns
        self.tiles = {x:Tile(x, x in goals, x in traps, x in walls) for x in range(1, rows*columns+1)}

        # Tell open tiles about their neighbors
        for label in set(self.tiles) - set(goals + traps + walls):
            tile = self.tiles[label]
            for action in Action:
                r, c = action.value
                neighbor = self.tile(r + (label-1) // columns, c + (label-1) % columns)
                # Make a list of neighboring tiles
                tile.neighbor[action] = neighbor if neighbor and not neighbor.wall
                tile.values[action] = 1 if neighbor and neighbor.wall else 0

    def tile(self, label, column):
        """Return tile at intersection of row and column.  Return None if row or column out of range"""
        if 0 <= label < self.rows and 0 <= column < self.columns:
            return self.tiles[label * self.columns + column + 1]
        return None