how can a function find the name by which it is called?

[Skaperen]

You could try inspect.stack()[1][4][0] and see if that is useful.

i tried it like this:

Output:
lt1a/forums/1 /home/forums 12> cat func_name.py
def foo(*args,**kwargs):
    import inspect
    me = inspect.stack()[1][4][0]
    print('i was called as',repr(me),flush=True)
    return me
bar = foo

print(f'woot {foo()},{bar(456)}',flush=True)
lt1a/forums/1 /home/forums 13> python3.8 func_name.py
i was called as "print(f'woot {foo()},{bar(456)}',flush=True)\n"
i was called as "print(f'woot {foo()},{bar(456)}',flush=True)\n"
woot print(f'woot {foo()},{bar(456)}',flush=True)
,print(f'woot {foo()},{bar(456)}',flush=True)

lt1a/forums/1 /home/forums 14>

but that was not what i wanted. i only want the name. with this i would need to parse the line (not too hard) and determine which name this call was (much harder).