Running Standard Scaler in Python 3

[deanhystad]

It is telling you that you cannot do this:

df3=pd.DataFrame(None)

Which is what you are doing because df2 == None. df2 == None because you cannot do this:

df2 = df.drop(["Unnamed: 0", "timestamp"], axis=1, inplace=True)

From the pandas documentation
https://pandas.pydata.org/pandas-docs/st....drop.html

inplacebool, default False
If False, return a copy. Otherwise, do operation inplace and return None.

So either you can do this:

df2 = df.drop(["Unnamed: 0", "timestamp"], axis=1)

Or you can do this:

df.drop(["Unnamed: 0", "timestamp"], axis=1, inplace=True)

Assignment of the result, and using "inplace=True" can never be used together