detect equal sequences in list

[Pedroski55]

Hanging position is: 1 to 3 and 5 to 8

As I understand it, you want the positions of the beginning and end of sequences of the same number in the list hash_list_film.

I don't understand what you are using hash for, maybe you are hashing a tuple?? But that wouldn't make a difference.

sequences is a list of lists of the start position of a sequence of the same number and the end position + 1

Thus, you could take each sub-list and loop through the numbers that are the same and do whatever you wish.

If hash_list_film ends with a sequence, that makes things awkward for my little function, so just append an X anyway.

What you do with the data in sequences is up to you!

def myApp():
    hash_list_film = ["12", "11", "11", "11", "17", "22", "22", "22", "22", "23", "24", "24", "24", "24" "X"]
    sequences = []
    count = 0
    def getSequence(start):
        tmp = [start]
        for k in range(start + 1, len(hash_list_film)-1):            
            # bale out of k loop at end of sequence
            if hash_list_film[k] != hash_list_film[k+1]:
                tmp.append(k+1)
                sequences.append(tmp)
                return k+1

    while count < len(hash_list_film) - 1:
        print(count)
        if hash_list_film[count] == hash_list_film[count+1]:
            count = getSequence(count)
        elif hash_list_film[count] != hash_list_film[count+1]:
            count +=1
    print(sequences)

Output:
[[1, 4], [5, 9], [10, 13]]