Is the following code returning a generator expression?

[Gribouillis]

Are the parenthesis part of the generator expression?

In a sense yes because there is no way to use them without parentheses. However when the generator expression is used as a single argument in a function call, the function call parentheses suffice

func(x is e or x == e for e in y)

If there is more than one argument, another pair of parentheses is necessary

func('spam', (x is e or x == e for e in y))

List comprehensions are like generator expressions but with square brackets.

[x is e or x == e for e in y]

They could also be written with a true generator expression

list(x is e or x == e for e in y)