dictionary insertion order

[DeaD_EyE]

If you also want to compare with insertion order, then use an OrderedDict.

from collections import OrderedDict

dx = {}
dx["a"] = 1
dx["b"] = 2
dx["c"] = 3

dy = {}
dy["c"] = 3
dy["b"] = 2
dy["a"] = 1

# The order is not checked
print("Dict equalness:", dx == dy)

# If you want include the order for comparison
# then use a OrderedDict
odx = OrderedDict(dx)
ody = OrderedDict(dy)

print("OrderedDict equalness:", odx == ody)

# and if you have an OrderedDict, but do not want to
# check the insertion order for equalness
print("OrderedDict -> dict equalness:", dict(odx) == dict(ody))


# or inline it
odx2 = OrderedDict({"a": 1, "b": 2, "c": 3})
ody2 = OrderedDict({"c": 3, "b": 2, "a": 1})

You could also check, if both dicts do have the same keys, without checking the values.

dx2 = {"a": 1, "b": 2, "c": 3}
dy2 = {"c": 30, "b": 20, "a": 10}

same_keys = not (dx2.keys() ^ dy2.keys())

if same_keys:
    print("dx2 and dy2 have the same keys")
    print("Values were not compared.")

The ordered dict does not return a set, if the key() method were called.
Instead, a list is returned. So you can check if the keys are the same and if they are in the same order.

dx3 = {"a": 1, "b": 2, "c": 3}
dy3 = {"c": 30, "b": 20, "a": 10}

odx3 = OrderedDict(dx3)
ody3 = OrderedDict(dy3)

same_keys = odx3.keys() == ody3.keys()

if same_keys:
    print("odx3 and ody3 have the same keys in the same order.")
    print("Values were not compared.")