update text variable on label with keypress

[menator01]

Sorry, just realized that this was an old post.

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You could do something like

import tkinter as tk 

class Action:
    def __init__(self):
        pass

    def kp(self, event, labels=[]):
        if event.keysym in ['a','b','c','d']:
            for label in labels:
                label.config(text=f'You pressed: {event.keysym.title()}')

    def reset(self, event, labels=[]):
        for label in labels:
            label.config(text='Default')


class Window:
    def __init__(self, parent):
        self.parent = parent
        parent.title('My Title Here')
        parent.geometry('800x600+250+250')
        parent.columnconfigure(0, weight=1)
        parent.rowconfigure(0, weight=1)

        container = tk.Frame(parent)
        container.grid(column=0, row=0, sticky='news')
        container.grid_columnconfigure(0, weight=3, uniform='text')
        container.grid_columnconfigure(1, weight=3)
        container.grid_columnconfigure(2, weight=3, uniform='text')

        self.left_label = tk.Label(container, relief='ridge', text='Default')
        self.left_label.grid(column=0, row=0, sticky='new')

        spacer = tk.Frame(container)
        spacer.grid(column=1, row=0, sticky='new')

        self.right_label = tk.Label(container, relief='ridge', text='Default')
        self.right_label.grid(column=2, row=0, sticky='new')


class Controller:
    def __init__(self, window, action):
        self.window = window
        self.action = action

        # Bind keys to action
        labels = [
            self.window.left_label,
            self.window.right_label
        ]
        self.window.parent.bind('<KeyPress>', lambda event:self.action.kp(event, labels=labels))
        self.window.parent.bind('<KeyRelease>', lambda event:self.action.reset(event, labels=labels))


if __name__ == '__main__':
    root = tk.Tk()
    controller = Controller(Window(root), Action())
    root.mainloop()