How to read a file as binary or hex "string" so that I can do regex search?

[snippsat]

Do not confuse the internal binary content with the displayed hex read in a hex editor.
The file’s raw data is binary,and the hex editor just helps you read it.
Must convert that binary data into a hex string in Python before treating it as something you can apply a [0-9A-Fa-f]{2} regex to it.

import re

with open("example1.txt", "rb") as hfile1:
    bfile1 = hfile1.read()

hex_string = bfile1.hex()
hex_string_space = ' '.join(f"{byte:02X}" for byte in bfile1)
print(hex_string_space)

Output:
3C 47 23 56 59 59 66 38 38 5C 67 3A 5A 70 29 32 47 25 28 63 5D 33 32 39 69 30 58 53 2B 4B 44 61 45 27 7A 3F 21 64 76 5B 54 5D 28 46 75 7A 52 5F

If look at raw data and wonder how it convert.

>>> bfile1
b"<G#VYYf88\\g:Zp)2G%(c]329i0XS+KDaE'z?!dv[T](FuzR_"

Output:
< = 3C,  G = 47, # = 23,...ect