If I need to do regex replacement 27000 times, how to shorten it?

[paul18fr]

with few informations and nothing to test, i would propose the following snippet:

import re
from _Arm64HexDatabase import *


inputVar = [
            "hex_suba64w0w0w0", 
            "hex_suba64w31w31w31", 
            "hex_suba64x0x0x0", 
            "hex_suba64x31x31x31", 
            ...
            ]

outputVar = [
             "hex_mova64w0c0", 
             "hex_mova64w31c0", 
             "hex_mova64x0c0", 
             "hex_mova64x31c0", 
             ...
             ]
# note: the 2 lists might be written once (and for all) in a file and loaded
#       the snippet assumes the pattern is exactly this one (otherwise if .. then ... must be used)

i = 0
with open ("example1", "rb") as handle_file1, open("result1.txt", "a") as hfile3:
    inputLine = handle_file1.readline()

    while (inputLine != ''):
        outputLine = re.sub(inputVar[i], outputVar[i], inputLine)
        hfile3.write(f"{outputLine}\n")
        i += 1
        inputLine = handle_file1.readline()