Jun-06-2017, 05:52 PM
You could also try parsing each individual character, and ignore non-numbers.
>>> x = '4234,093.23'
>>> def try_int(ch):
... try:
... _ = int(ch)
... return True
... except ValueError:
... pass
... return False
...
>>> ''.join(filter(try_int, x))
'423409323'
>>> # the decimal is included, so instead, we should split that out ahead of time...
...
>>> left, *_ = x.split(".")
>>> left
'4234,093'
>>> ''.join(filter(try_int, left))
'4234093'Using filter() would probably be a pretty good hint that you got outside assistance, though :p
