Zip on single element in nested sequence.

[nilamo]

Yeah, that would work for n=2, but it doesn't seem super elegant to me. I wish there was something in itertools to get the nth item of an iterator.

Seems easy enough to make, though:

>>> def nth(ndx, collection):
...   last = None
...   for _ in range(0, ndx+1):
...     last = next(collection)
...   return last
...
>>> a = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
>>> nth(1, zip(*a))
(2, 5, 8)

Or if you prefer comprehensions:

>>> def nth(ndx, collection):
...   vals = [next(collection) for _ in range(0, ndx+1)]
...   return vals[-1]
...
>>> a = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
>>> nth(1, zip(*a))
(2, 5, 8)