Python Calculator Application

[snippsat]

Is there anything that I could improve on in terms of simplicity or better ways of getting the job done?

Yes
The effort is good,but there are really big problem is your design of this.
I will not at all try to fix your code,but give a example with design in focus.
It's scary that you call the main() function 14 times

Some point i name the function menu() not main(),
a lot people use main() but name no sense because it can be everything.
menu() is just called 1 time,after calculate always fall back into menu() again.
There can make new calculation or Quit out.

from operator import add, sub, mul

def calc():
   op = input("Enter operator +-*: ")
   n1 = int(input('Fist number: '))
   n2 = int(input('Second number: '))
   operators = {'+': add(n1, n2), '-': sub(n1, n2), '*': mul(n1, n2)}
   if op in operators:
       print('{} {} {} = {}'.format(n1, op, n2, operators[op]))
   input('Press enter to return menu\n')

def menu():
   while True:
       print('(1) Calculate 2 numbers')
       print('(Q) Quit')
       choice = input('Enter your choice: ').lower()
       if choice == '1':
           calc()
       elif choice == 'q':
           return False
       else:
           print('Not a correct choice: <{}>,try again'.format(choice))

if __name__ == '__main__':
   menu()

A run:

Output:
C:\1_py\div
λ python calc.py
(1) Calculate 2 numbers
(Q) Quit
Enter your choice: aaaa
Not a correct choice: <aaaa>,try again
(1) Calculate 2 numbers
(Q) Quit
Enter your choice: 1
Enter operator +-*: *
Fist number: 6
Second number: 7
6 * 7 = 42
Press enter to return menu

(1) Calculate 2 numbers
(Q) Quit
Enter your choice: q

C:\1_py\div
λ