list of list to list of tuple?

[student8]

How do I convert this list of lists:

[['0', '1'], ['0', '2'], ['0', '3'], ['1', '4'], ['1', '6'], ['1', '7'], ['1', '9'], ['2', '3'], ['2', '6'], ['2', '8'], ['2', '9']]

To this list of tuples:

[(0, [1, 2, 3]), (1, [0, 4, 6, 7, 9]), (2, [0, 3, 6, 8, 9])]

I am unsure how to implement this next step? (I can't use dictionaries,
sets, deque, bisect module. You can though, and in fact should, use .sort or sorted functions.)

Here is my attempt:

    network= [['10'], ['0 1'], ['0 2'], ['0 3'], ['1 4'], ['1 6'], ['1 7'], ['1 9'], ['2 3'], ['2 6'], ['2 8'], ['2 9']]
    network.remove(network[0])
    friends=[]
    
    for i in range(len(network)):
        element= (network[i][0]).split(' ')
        friends.append(element)
    
    
    t=len(friends)
    lst=[]
    
    for i in range(t):
        a= (friends[i][0])
        if a not in lst:
            lst.append(int(a))
            for i in range(t):
                if a == friends[i][0]:
                    b=(friends[i][1])
                    lst.append([b])
    print(tuple(lst))

It outputs:

  (0, ['1'], ['2'], ['3'], 0, ['1'], ['2'], ['3'], 0, ['1'], ['2'], ['3'], 1, ['4'], ['6'], ['7'], ['9'], 1, ['4'], ['6'], ['7'], ['9'], 1, ['4'], ['6'], ['7'], ['9'], 1, ['4'], ['6'], ['7'], ['9'], 2, ['3'], ['6'], ['8'], ['9'], 2, ['3'], ['6'], ['8'], ['9'], 2, ['3'], ['6'], ['8'], ['9'], 2, ['3'], ['6'], ['8'], ['9'])

I am very close it seems, but not sure what to do??