here is another 2.7 to 3.5 convert

[snippsat]

what is a  remote_ip = '111.111.111, that only have 3 set of numbers, most ip have 4 set of numbers 111.111.111.111?

It could have been any number,i was just showing what was wrong with this line:

print ('Ip address of ') + host + ' is ' + remote_ip # ) wrong placement

The correct and best way:

print('Ip address of {} is {}'.format(host, remote_ip))

Have you not look into now how interactive interpreter work?


You can try this code:

import socket   
import sys

try:    
    s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
except socket.error as msg:
    print('Failed to create socket. Error code: {}'.format(str(msg)))
    sys.exit()

print('Socket Created')
host = 'www.google.com'
port = 80

try:
    remote_ip = socket.gethostbyname(host)
except socket.gaierror:
    print('Hostname could not be resolved. Exiting')
    sys.exit()

print('Ip address of {} is {}'.format(host, remote_ip))
s.connect((remote_ip , port))
print('Socket Connected to {} on ip {}'.format(host, remote_ip))