getting the source line number

[Larz60+]

You can filter the line number out. Here's a simple class that does that:

import inspect

class GetCallStackItem:
    def __init__(self):
        self.full_stack = inspect.stack()
        for stacklevel, item in enumerate(self.full_stack):
            attributes = self.get_method_attributes(item)
            print(f'\nstacklevel: {stacklevel}')
            for attrname, value in attributes:
                if attrname == 'lineno':
                    print(f'line Number: {value}')

    def get_method_attributes(self, method):
        temp = dir(type('whatever', (object,), {}))
        return [item for item in inspect.getmembers(method) if item[0] not in temp]


if __name__ == '__main__':
    gcsi = GetCallStackItem()

Running this on itself returns the following:

Output:
stacklevel: 0
line Number: 5

stacklevel: 1
line Number: 19

If you add a print statement immediately after the second for statement, you'll get an exhaustive of all that's available.
There may be more stuff that would like to extract.