Timed Exit

[DeaD_EyE]

If seen this question one time before. The solution was a trick.
You can use signaling to enforce calling some function and
finally this function raises an TimeoutError which bubbles up.
The minimal implementation as a context manager:

class TimeOut:
    def __init__(self, timeout):
        self.timeout = timeout
        self._orig_handler = signal.signal(signal.SIGALRM, self._timeout)
    def __enter__(self):
        signal.alarm(self.timeout)
        return self
    def __exit__(self, *args):
        signal.signal(signal.SIGALRM, self._orig_handler)
    def _timeout(self, *args):
        raise TimeoutError

Using the context manager:

with TimeOut(5):
    input('Answer in 5 seconds: ')

Error:
---------------------------------------------------------------------------
TimeoutError                              Traceback (most recent call last)
<ipython-input-38-304f3fa31b18> in <module>()
      1 with TimeOut(5):
----> 2     input('Answer in 5 seconds: ')
      3 

<ipython-input-32-8635f61b6ed0> in _timeout(self, *args)
      9         signal.signal(signal.SIGALRM, self._orig_handler)
     10     def _timeout(self, *args):
---> 11         raise TimeoutError
     12 

TimeoutError:

Now you have to catch the TimoutError Exception, which bubbles up:

with TimeOut(5):
    try:
        input('Answer in 5 seconds: ')
    except TimeoutError:
        print('\nTime is up!')

Output:
Answer in 5 seconds: 
Time is up!