for any loop _ want to know which matches

[buran]

like I did in my first post: I declared output1, output2 as empty lists. Because if I wouldn't I won't be able to append values to it

If I would want to turn a number of results in a list, I could just define it on the spot ...

Right?

yes, that's correct.
note that result initially is list of lists, so you unpack the outer list in respective number of variables

result = [['a', 'b', 'c'], [1, 2, 3]]
o1, o2 = result
print(o1)
print(o2)

Output:
['a', 'b', 'c']
[1, 2, 3]
>>>