How to exclude characters when counting digits

[volcano63]

import string
def count_func(s):
    return sum(1 for c in s if c in set(string.digits))

It may be re-written as

def count_func(s):
    return sum(c in set(string.digits) for c in s)

You can add booleans as integers.

Still, major loser to @ichabod801

Output:
In [8]: %timeit dead_eye_count_func(my_string)
31.8 ms ± 1 ms per loop (mean ± std. dev. of 7 runs, 10 loops each)

In [9]: %timeit ick_count(my_string)
467 µs ± 12 µs per loop (mean ± std. dev. of 7 runs, 1000 loops each)

With a little tweak - making set of digits "static"

Output:
In [12]: def frozen_set_count_func(s, _digits=frozenset(string.digits)):
    ...:     return sum(c in _digits for c in s)
    ...: 

In [13]: %timeit frozen_set_count_func(my_string)
5.7 ms ± 264 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)