.remove() method in for-loop

[ichabod801]

Yes, but set will change the order and remove duplicates. That may be desired behavior. And you didn't test filter. If you add

def time_5(lst):
    sw = filter(lambda item: item != 'bo', lst)

Then the short list times are:

Output:
time_1 --> 9.78
time_2 --> 4.95
time_3 --> 6.95
time_4 --> 7.73
time_5 --> 3.40

And the long list times are:

Output:
time_1 --> 4.09
time_2 --> 0.18
time_3 --> 0.07
time_4 --> 7.32
time_5 --> 0.03