Why is subprocess.call command not working?

[zBernie]

Line 4, 3 quotes.
You have to break the command by spaces.

command = "convert " + str(jpgfile) + " -font Helvetica -pointsize 60 -fill lightblue -quality 100 -gravity southeast -auto-orient -annota"
command = command.split()

Now I'm getting the error below.

-Thanks

jpgdir = "/home/bernie/CentOS Share/pics/"
jpgfiles = fnmatch.filter(os.listdir(jpgdir), '*.jpg')

command = "convert " + str(jpgfile) + " -font Helvetica -pointsize 60 -fill lightblue -quality 100 -gravity southeast -auto-orient -annotate +80+50 %[exif:DateTimeOriginal] " + str(jpgfile)
    command = command.split()

    subprocess.call([command])

Error:
Traceback (most recent call last):
  File "./im-datestamp.py", line 36, in <module>
    subprocess.call([command])
  File "/opt/rh/rh-python36/root/usr/lib64/python3.6/subprocess.py", line 267, in call
    with Popen(*popenargs, **kwargs) as p:
  File "/opt/rh/rh-python36/root/usr/lib64/python3.6/subprocess.py", line 709, in __init__
    restore_signals, start_new_session)
  File "/opt/rh/rh-python36/root/usr/lib64/python3.6/subprocess.py", line 1258, in _execute_child
    executable = os.fsencode(executable)
  File "/opt/rh/rh-python36/root/usr/lib64/python3.6/os.py", line 800, in fsencode
    filename = fspath(filename)  # Does type-checking of `filename`.
TypeError: expected str, bytes or os.PathLike object, not list