Help to find a command

[perfringo]

Sorry, but it doesn't click... You always append number 1, there is no way to determine in which order flaws occur. You can set tension to min value and find whether there are strengths which are some predefined range.

Something like that:

>>> fiber = [[77, 2], [16, 5], [36, 11], [7, 12], [93, 15], [42, 17], [82, 18], [33, 33], [79, 42], [94, 43]]
>>> tension = min(fiber, key=lambda x: x[0])[0]
>>> tension
7
>>> r = 10                # arbitrary range from breakpoint
>>> [strength + [1] if tension + r >= strength[0] else strength for strength in fiber]
[[77, 2],
 [16, 5, 1],
 [36, 11],
 [7, 12, 1],
 [93, 15],
 [42, 17],
 [82, 18],
 [33, 33],
 [79, 42],
 [94, 43]]

If r = 87 then 1 will be appended to all elements and nobody is any wiser.


Side observation:

- random.randint(0, 100) may include both 0 and 100:

>>> help(random.randint)
Help on method randint in module random:

randint(a, b) method of random.Random instance
    Return random integer in range [a, b], including both end points.
(END)

I believe that fiber cannot break at start and endpoint i.e. at length 0 and 100. In order to avoid surprises it's good to use range like (1, 99) or something.

EDIT: with subjectively better naming:

>>> [[strength, position, 1] if tension + r >= strength else [strength, position] for [strength, position] in fiber]