how do I show 12 numbers from a huge number?

[anabeatriz]

I have to look in my Math-book. Maybe there is a solution: http://weitz.de/KMFI/ The book is good, but it's only in German. He uses Python to explain math.

---

With modular arithmetic you get the last x digits of the solution. The built-in function pow supports it. The equation is: 2 ** (2 ** 34)

pow(2, 2**34, 10**12)

This should calculate the last 12 digits of 2 ** (2**34)

---

The other solution to get the first x digits can may be done with iteration.

 def ipow(x, y, digits): for _ in range(y - 1): x *= x # do something to truncate x? # maybe working with math.log10 

By the way, this question is very old: https://stackoverflow.com/questions/6351...e-required Another solution is the usage of math.log10: https://stackoverflow.com/questions/3873...nentiation

 def get_first_digits(a, b, n): x = b * math.log10(a) y = math.floor(pow(10, x - math.floor(x) + n - 1)) return int(y) 

Output:
 In [65]: get_first_digits(2,2**34,12) Out[65]: 927436539881 

Thank you, I will show 927436539881 to my teacher and then you will know his answer