Do something with all possible combinations of a list

[newbieAuggie2019]

It does leave out the 'themselves'-ones but not the duplicate matches.

In my case [1,6] will return the same result (if doing a function) as [6,1]

I think I found a way:

listA = [1,2,3,4,5,6]
listB = listA[:]
output = []
for a in listA: 
    for b in listB:
        if b != a and b > a:
            # function here
            output.append([a,b])
print(output)

and that little modification produces the following output:

Output:
[[1, 2], [1, 3], [1, 4], [1, 5], [1, 6], [2, 3], [2, 4], [2, 5], [2, 6], [3, 4], [3, 5], [3, 6], [4, 5], [4, 6], [5, 6]]

All the best,